Quaderno 4 Soluzioni _ Scheda 1 VERSO GLI OBIETTIVI MINIMI 31,4 cm h 1 = ___ 360°= _________ 360°= 120° 2 r 2 15 cm 135° 2 h = ____ 2 r = ____ 2 4 cm = 9,4 cm. 360° 360° 15° 18° 3 x = ____ = ____ = ___ x = ____ = ____ = ___ 180° 180° 12 180° 180° 10 108° 3 x = ____ = ____ = ___ 180° 180° 5 3 ___ 180° x 180° 10 4 = _______ = _________ = 54° _5_ 180° 6 = 130°; = ________ = 150° 5 sen90° = 1; cos90° = 0 sen180° = 0; cos180° = 1 sen270° = 1; cos270° = 0 6 _ _ _ 3 3 1 13 = 6 3 __ + 2 ___ 3 ___ = 3 3 2 2 3 14 negativo 1 15 __ 2 16 cos( x) = cosx; senx( senx) + cosxcosx = 1 senx sen2x ( cosx) = 17 senx( ____) 1 + _________ cosx ( cos2x) _ _ 3 3 1 ___ 1 + ___ 2_ 2_ _______ _______ + = 18 2 2 1 + ___ 1 ___ 2 2 __ __ __ __ __ 19 sen( x) = senx; senx + 2senx + cosx = 3senx + cosx 20 y 1 y 1 1 4 1 __ 2 3 6 2 3 6 1 ___ ___ + ___ + 1 + ___ + ___ + ___ _ 2 2 4 2 2 4 ____________________________________ = = 4 + 6 1 1 __ 2 O 3 2 A 1 O 2 2 1 3 2 x 2 x 1 y 1 parallela; OA 7 3 2 2 y 1 O 2 1 3 2 x 2 2 B 1 O asse x 3 4 1 x y 1 1 _3_; OB 4 8 = 2 +1 = 3 sen2x sen2x _____ 9 = ________ +3=3 2 cos x cos2x cosx[1 cos2x] senx 1 = 10 = _____________ _ cos2x + ________ senx cosx sen2x _____ 1+ cos2x 2 cos x = cosxsenx senxcosx + _______________ = cos2x sen2x + cos2x 11 = 7 1 4 0 + 2 1 = 5 12 cos(__ __) = sen__; sen(__ __) = cos__ 3_ 3 2 4 4 _2 _ _ _ 3 2 2 2 + 5 3_ 1 ___ ___ _ _ _ ________ +2 3 +4 1 3= 2 +4= =2 2 2 2 2 2 86 3 2 2 O 2 1 3 2 2 x 2 21 y 1 2 O 1 2 2 3 2 2 5 2 x